Mutual position of two straight lines -2
author: Петя
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Let's assume that two straight lines g1 and g2 are defined by the equations: g1: A1x+ B1y+ C1 = 0, g2:A2x+ B2y + C2 = 0.
We know that the two straight lines fuse together when the coefficients in their equations are proportionately, i.e. when a number v exists, that (1) А2 = vA1, B2 = vB1, C2 = vB1.
When the condition (1) is present, the straight lines g1 and g2 are intersecting or parallel. Which one of the two cases is available can be understood by solving the system (2)
A1x + B1y + C1 = 0
A2x + B2y + C2 = 0
If the system (2) has one solution (х1; у1), the point М1 (х1; у1) satisfies the equations of the two straight lines g1 and g2, i.е g1 and g2 are intesected in point М1.
If the system (2) has no solution the straight lines g1 and g2 don't have a common point, i.е. they are parallel.
The mutual position of g1 and g2 can be defined also without solving the system (2).
We know that the vectors u1 →(-B1; A1) and u2 →(-B2;A2) are collinear respectively to the straight lines g1 and g2. The straight lines are parallel if and only if the vectors u1 →and u2→ are collinear, i.е. when a number v exist that u2 → = vu1 →. Then А2 = vA1, B2 = vB1.
- are parallel if А2 = vA1, B2 = vB1, but С is different from vC1, i.е. the coefficient in front of х and у in their equations are proportionately, but this proportionality isn't standed by the free terms;
- are collineral if the coefficient before х and у in their equations aren't proportionately (А1/А2 is different from В1/В2).
In case of the two straight lines have Cartesian equations g1: y = k1x+ n1, g2:y = k2x + n2, having in mind geometrical meaning of the angular coefficient and the segment of the от axis Оу, are the following conditions emerge about the mutual different positions of the two straight lines:
1. k1 different from k2 - g1 and g2 are collineral;
2. k1 = k2, n1 different from n2 - g1 and g2 are parallel;
3. k1 = k2, n1 = n2 - g1 and g2 are merged.